February 24, 201115 yr i made this spatula in a trade to a friend of mine at the foundry. he had cast a BIG skillet and needed a long spatula for it and asked if i could make him one, it just so happened that i was planning on asking if he could cast me a swage block if i made the pattern for it. so for this spatula i not only got the swage block cast but also got a cone mandrelcast as well. even though, i really hated to let it go. oh well, i can make another one! maybe. anyway, the handle is forged from 1/2" square bar and it's about 2 feet long, (i say "about" because i didn't remember to measure it) and the blade is riveted on in three places with some 3/16" copper wire. the end of the blade is thinned to make getting under items easier, and on one side of the handle is my full name (that was fun to stamp). on the opposite is Joel T. (his name), that one is pretty easy. Ed Steinkirchner
February 25, 201115 yr we need pictures of the swage block and cone! Thats a nice looking spatula. Those are the friends that are good to know.
February 25, 201115 yr Author The only pics that i have of the block on this computer are of the wooden mold and one of the finished one in the shop. is weighed 88 lbs rough cast(which is when i got it) and is closer to square than rectangular in CS. it isn't for heavy forging, especially the half rounds, since they're kind of thin between each other. I'm just going to make anvil swages for swaging actual dimensions. i use it a lot for sheet metal, curving gouges, and other such things. i use the rivet head divots and the bowls on the sides the most. the big 2 inch round is not esed much because i messed up and cut the end backwards. the shovel mold is very nice to have and i didn't realize it until i tried making one without one. i don't have a pic of the cone but it is 13 inches tall and 4 inches at the base, and probably weighs 25 lbs. strangely enough, the small dimension of the swage block is exactly the same as my anvil face(4 inches)and 6 inches the tall way. I'm not sure as to the overall length. kind of a long reply, but i hope it answered some questions. Ed Steinkirchner
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