TASMITH Posted November 28, 2008 Share Posted November 28, 2008 (edited) I don't know how many of you have run into this little problem before, but if you have then this is formula is tops! i have run into the problem in the past of needing something, such as an acid solution, that needed a certain percentage or concentration of the chemical. Say for example you want to etch a pattern in a knife but the etching solution (we will say an acid solution for example purposes) is a 25% solution, but you want it a little more dilute to have better control over the etching rate. How do you calculate how much water do you mix with the acid you have to make it a 15% solution? This little formula works like a charm and gives you very accurate results.It is a simple little subtraction formula that anyone can do. To begin with write down the following letters on a sheet of paper.A BDXY (To make it simpler to use write the letters across the page rather than down as shown in this post.Keep a good separation between the letters) To figure out a percentage dilution: 1.Place the percentage strength of the solution to be diluted at A 2.Put the percentage of the diluting solution at B (water should be entered as 0 ) 3.Place the desired percentage at D 4.Subtract D from A and place the answer at Y 5.Subtract B from D and place the answer at X Then mix X parts of A with Y parts of B to make the percent solution listed at D. Example 1 Using the numbers from above ( 25% solution, needing 15% solution) using water to dilute:A - 25B - 0D - 15X - 15Y - 10 Following steps 1 to 5 from above you would mix 15 parts of 25% acid solution with 10 parts water to get a 15% acid solution. Example 2 You have a 25% solution of acid and a 10% solution of acid but you want an 18% solution of acid.In this case we will be using the weaker acid to dilute the stronger one down to the percentage req'd. Using this same formula:A - 25.B - 10D - 18X - 8Y - 7 Again following steps 1 through 5 above you would mix 7 parts of 25% acid with 8 parts of 10% acid to make a 18% solution of acid. This seems a little confusing when you first start to use it but after you have done it a couple of times it is really quite simple to do.Just use the numbers I provided in the examples and work it out yourselves a couple of times then work in your own numbers for practice. It is surprising how easy it becomes to use it. TerryAlways add acid to water, or a stronger acid to a weaker, to prevent splashing Edited June 27, 2009 by mod07 edited typo for safety Quote Link to comment Share on other sites More sharing options...
Sask Mark Posted November 28, 2008 Share Posted November 28, 2008 The simple formula we used to perform this dilution in the chemistry labs was: C1V1 = C2V2 Where C=concentration and V=volume. A little algebra will help you calculate the unknown variable. For example, you have 100ml of 25% acid that you want to make 15%. 25 X 100 = 15 X V2 (25 X 100) / 15 = V2 167 = V2 so you would have to add 67ml of water to the original 100 ml of 25% acid to get 15% solution. As a note for acid dilutions ALWAYS add water to concentrated acid, NEVER add concentrated acid to water. Quote Link to comment Share on other sites More sharing options...
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