Blacksmith and Metalworking Forum
This is a discussion on Changing a Percentage Solution within the Alchemy and Formulas forums, part of the Blacksmithing category; I don't know how many of you have run into this little problem before, but if you have then this ...
| |||||||
| Register | FAQ | Calendar | Search | Today's Posts | Mark Forums Read |
| |||
|
I don't know how many of you have run into this little problem before, but if you have then this is formula is tops! i have run into the problem in the past of needing something, such as an acid solution, that needed a certain percentage or concentration of the chemical. Say for example you want to etch a pattern in a knife but the etching solution (we will say an acid solution for example purposes) is a 25% solution, but you want it a little more dilute to have better control over the etching rate. How do you calculate how much water you add to the acid you have to make it a 15% solution? This little formula works like a charm and gives you very accurate results.It is a simple little subtraction formula that anyone can do. To begin with write down the following letters on a sheet of paper. A B D X Y (To make it simpler to use write the letters across the page rather than down as shown in this post.Keep a good separation between the letters) To figure out a percentage dilution: 1.Place the percentage strength of the solution to be diluted at A 2.Put the percentage of the diluting solution at B (water should be entered as 0 ) 3.Place the desired percentage at D 4.Subtract D from A and place the answer at Y 5.Subtract B from D and place the answer at X Then mix X parts of A with Y parts of B to make the percent solution listed at D. Example 1 Using the numbers from above ( 25% solution, needing 15% solution) using water to dilute: A - 25 B - 0 D - 15 X - 15 Y - 10 Following steps 1 to 5 from above you would mix 15 parts of 25% acid solution with 10 parts water to get a 15% acid solution. Example 2 You have a 25% solution of acid and a 10% solution of acid but you want an 18% solution of acid.In this case we will be using the weaker acid to dilute the stronger one down to the percentage req'd. Using this same formula: A - 25. B - 10 D - 18 X - 8 Y - 7 Again following steps 1 through 5 above you would mix 7 parts of 25% acid with 8 parts of 10% acid to make a 18% solution of acid. This seems a little confusing when you first start to use it but after you have done it a couple of times it is really quite simple to do.Just use the numbers I provided in the examples and work it out yourselves a couple of times then work in your own numbers for practise. It is surprising how easy it becomes to use it. Terry |
| |||
|
The simple formula we used to perform this dilution in the chemistry labs was: C1V1 = C2V2 Where C=concentration and V=volume. A little algebra will help you calculate the unknown variable. For example, you have 100ml of 25% acid that you want to make 15%. 25 X 100 = 15 X V2 (25 X 100) / 15 = V2 167 = V2 so you would have to add 67ml of water to the original 100 ml of 25% acid to get 15% solution. As a note for acid dilutions ALWAYS add water to concentrated acid, NEVER add concentrated acid to water. |